Integrand size = 21, antiderivative size = 222 \[ \int (a+b \cos (c+d x))^4 \sec ^7(c+d x) \, dx=\frac {\left (5 a^4+36 a^2 b^2+8 b^4\right ) \text {arctanh}(\sin (c+d x))}{16 d}+\frac {4 a b \left (4 a^2+5 b^2\right ) \tan (c+d x)}{5 d}+\frac {\left (5 a^4+36 a^2 b^2+8 b^4\right ) \sec (c+d x) \tan (c+d x)}{16 d}+\frac {a^2 \left (5 a^2+32 b^2\right ) \sec ^3(c+d x) \tan (c+d x)}{24 d}+\frac {7 a^3 b \sec ^4(c+d x) \tan (c+d x)}{15 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}+\frac {4 a b \left (4 a^2+5 b^2\right ) \tan ^3(c+d x)}{15 d} \]
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Time = 0.46 (sec) , antiderivative size = 222, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2871, 3110, 3100, 2827, 3852, 3853, 3855} \[ \int (a+b \cos (c+d x))^4 \sec ^7(c+d x) \, dx=\frac {7 a^3 b \tan (c+d x) \sec ^4(c+d x)}{15 d}+\frac {4 a b \left (4 a^2+5 b^2\right ) \tan ^3(c+d x)}{15 d}+\frac {4 a b \left (4 a^2+5 b^2\right ) \tan (c+d x)}{5 d}+\frac {a^2 \left (5 a^2+32 b^2\right ) \tan (c+d x) \sec ^3(c+d x)}{24 d}+\frac {a^2 \tan (c+d x) \sec ^5(c+d x) (a+b \cos (c+d x))^2}{6 d}+\frac {\left (5 a^4+36 a^2 b^2+8 b^4\right ) \text {arctanh}(\sin (c+d x))}{16 d}+\frac {\left (5 a^4+36 a^2 b^2+8 b^4\right ) \tan (c+d x) \sec (c+d x)}{16 d} \]
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Rule 2827
Rule 2871
Rule 3100
Rule 3110
Rule 3852
Rule 3853
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \frac {a^2 (a+b \cos (c+d x))^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}+\frac {1}{6} \int (a+b \cos (c+d x)) \left (14 a^2 b+a \left (5 a^2+18 b^2\right ) \cos (c+d x)+3 b \left (a^2+2 b^2\right ) \cos ^2(c+d x)\right ) \sec ^6(c+d x) \, dx \\ & = \frac {7 a^3 b \sec ^4(c+d x) \tan (c+d x)}{15 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}-\frac {1}{30} \int \left (-5 a^2 \left (5 a^2+32 b^2\right )-24 a b \left (4 a^2+5 b^2\right ) \cos (c+d x)-15 b^2 \left (a^2+2 b^2\right ) \cos ^2(c+d x)\right ) \sec ^5(c+d x) \, dx \\ & = \frac {a^2 \left (5 a^2+32 b^2\right ) \sec ^3(c+d x) \tan (c+d x)}{24 d}+\frac {7 a^3 b \sec ^4(c+d x) \tan (c+d x)}{15 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}-\frac {1}{120} \int \left (-96 a b \left (4 a^2+5 b^2\right )-15 \left (5 a^4+36 a^2 b^2+8 b^4\right ) \cos (c+d x)\right ) \sec ^4(c+d x) \, dx \\ & = \frac {a^2 \left (5 a^2+32 b^2\right ) \sec ^3(c+d x) \tan (c+d x)}{24 d}+\frac {7 a^3 b \sec ^4(c+d x) \tan (c+d x)}{15 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}+\frac {1}{5} \left (4 a b \left (4 a^2+5 b^2\right )\right ) \int \sec ^4(c+d x) \, dx-\frac {1}{8} \left (-5 a^4-36 a^2 b^2-8 b^4\right ) \int \sec ^3(c+d x) \, dx \\ & = \frac {\left (5 a^4+36 a^2 b^2+8 b^4\right ) \sec (c+d x) \tan (c+d x)}{16 d}+\frac {a^2 \left (5 a^2+32 b^2\right ) \sec ^3(c+d x) \tan (c+d x)}{24 d}+\frac {7 a^3 b \sec ^4(c+d x) \tan (c+d x)}{15 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}-\frac {1}{16} \left (-5 a^4-36 a^2 b^2-8 b^4\right ) \int \sec (c+d x) \, dx-\frac {\left (4 a b \left (4 a^2+5 b^2\right )\right ) \text {Subst}\left (\int \left (1+x^2\right ) \, dx,x,-\tan (c+d x)\right )}{5 d} \\ & = \frac {\left (5 a^4+36 a^2 b^2+8 b^4\right ) \text {arctanh}(\sin (c+d x))}{16 d}+\frac {4 a b \left (4 a^2+5 b^2\right ) \tan (c+d x)}{5 d}+\frac {\left (5 a^4+36 a^2 b^2+8 b^4\right ) \sec (c+d x) \tan (c+d x)}{16 d}+\frac {a^2 \left (5 a^2+32 b^2\right ) \sec ^3(c+d x) \tan (c+d x)}{24 d}+\frac {7 a^3 b \sec ^4(c+d x) \tan (c+d x)}{15 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^5(c+d x) \tan (c+d x)}{6 d}+\frac {4 a b \left (4 a^2+5 b^2\right ) \tan ^3(c+d x)}{15 d} \\ \end{align*}
Time = 0.65 (sec) , antiderivative size = 154, normalized size of antiderivative = 0.69 \[ \int (a+b \cos (c+d x))^4 \sec ^7(c+d x) \, dx=\frac {15 \left (5 a^4+36 a^2 b^2+8 b^4\right ) \text {arctanh}(\sin (c+d x))+\tan (c+d x) \left (15 \left (5 a^4+36 a^2 b^2+8 b^4\right ) \sec (c+d x)+10 a^2 \left (5 a^2+36 b^2\right ) \sec ^3(c+d x)+40 a^4 \sec ^5(c+d x)+64 a b \left (15 \left (a^2+b^2\right )+5 \left (2 a^2+b^2\right ) \tan ^2(c+d x)+3 a^2 \tan ^4(c+d x)\right )\right )}{240 d} \]
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Time = 6.02 (sec) , antiderivative size = 209, normalized size of antiderivative = 0.94
method | result | size |
derivativedivides | \(\frac {a^{4} \left (-\left (-\frac {\left (\sec ^{5}\left (d x +c \right )\right )}{6}-\frac {5 \left (\sec ^{3}\left (d x +c \right )\right )}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )-4 a^{3} b \left (-\frac {8}{15}-\frac {\left (\sec ^{4}\left (d x +c \right )\right )}{5}-\frac {4 \left (\sec ^{2}\left (d x +c \right )\right )}{15}\right ) \tan \left (d x +c \right )+6 a^{2} b^{2} \left (-\left (-\frac {\left (\sec ^{3}\left (d x +c \right )\right )}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-4 a \,b^{3} \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )+b^{4} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}\) | \(209\) |
default | \(\frac {a^{4} \left (-\left (-\frac {\left (\sec ^{5}\left (d x +c \right )\right )}{6}-\frac {5 \left (\sec ^{3}\left (d x +c \right )\right )}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )-4 a^{3} b \left (-\frac {8}{15}-\frac {\left (\sec ^{4}\left (d x +c \right )\right )}{5}-\frac {4 \left (\sec ^{2}\left (d x +c \right )\right )}{15}\right ) \tan \left (d x +c \right )+6 a^{2} b^{2} \left (-\left (-\frac {\left (\sec ^{3}\left (d x +c \right )\right )}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-4 a \,b^{3} \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )+b^{4} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}\) | \(209\) |
parts | \(\frac {a^{4} \left (-\left (-\frac {\left (\sec ^{5}\left (d x +c \right )\right )}{6}-\frac {5 \left (\sec ^{3}\left (d x +c \right )\right )}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )}{d}+\frac {b^{4} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}-\frac {4 a^{3} b \left (-\frac {8}{15}-\frac {\left (\sec ^{4}\left (d x +c \right )\right )}{5}-\frac {4 \left (\sec ^{2}\left (d x +c \right )\right )}{15}\right ) \tan \left (d x +c \right )}{d}+\frac {6 a^{2} b^{2} \left (-\left (-\frac {\left (\sec ^{3}\left (d x +c \right )\right )}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}-\frac {4 a \,b^{3} \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )}{d}\) | \(220\) |
parallelrisch | \(\frac {-1125 \left (a^{4}+\frac {36}{5} a^{2} b^{2}+\frac {8}{5} b^{4}\right ) \left (\frac {\cos \left (6 d x +6 c \right )}{15}+\frac {2 \cos \left (4 d x +4 c \right )}{5}+\cos \left (2 d x +2 c \right )+\frac {2}{3}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+1125 \left (a^{4}+\frac {36}{5} a^{2} b^{2}+\frac {8}{5} b^{4}\right ) \left (\frac {\cos \left (6 d x +6 c \right )}{15}+\frac {2 \cos \left (4 d x +4 c \right )}{5}+\cos \left (2 d x +2 c \right )+\frac {2}{3}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\left (850 a^{4}+6120 a^{2} b^{2}+720 b^{4}\right ) \sin \left (3 d x +3 c \right )+\left (150 a^{4}+1080 a^{2} b^{2}+240 b^{4}\right ) \sin \left (5 d x +5 c \right )+\left (7680 a^{3} b +5760 a \,b^{3}\right ) \sin \left (2 d x +2 c \right )+\left (3072 a^{3} b +3840 a \,b^{3}\right ) \sin \left (4 d x +4 c \right )+\left (512 a^{3} b +640 a \,b^{3}\right ) \sin \left (6 d x +6 c \right )+1980 \left (a^{4}+\frac {28}{11} a^{2} b^{2}+\frac {8}{33} b^{4}\right ) \sin \left (d x +c \right )}{240 d \left (\cos \left (6 d x +6 c \right )+6 \cos \left (4 d x +4 c \right )+15 \cos \left (2 d x +2 c \right )+10\right )}\) | \(322\) |
risch | \(-\frac {i \left (-640 a \,b^{3}-512 a^{3} b -3072 a^{3} b \,{\mathrm e}^{2 i \left (d x +c \right )}-5120 a^{3} b \,{\mathrm e}^{6 i \left (d x +c \right )}-3840 a \,b^{3} {\mathrm e}^{2 i \left (d x +c \right )}-540 a^{2} b^{2} {\mathrm e}^{i \left (d x +c \right )}-3060 a^{2} b^{2} {\mathrm e}^{3 i \left (d x +c \right )}-1920 a \,b^{3} {\mathrm e}^{8 i \left (d x +c \right )}+3060 a^{2} b^{2} {\mathrm e}^{9 i \left (d x +c \right )}-7680 a \,b^{3} {\mathrm e}^{4 i \left (d x +c \right )}+540 a^{2} b^{2} {\mathrm e}^{11 i \left (d x +c \right )}-6400 a \,b^{3} {\mathrm e}^{6 i \left (d x +c \right )}-2520 a^{2} b^{2} {\mathrm e}^{5 i \left (d x +c \right )}+2520 a^{2} b^{2} {\mathrm e}^{7 i \left (d x +c \right )}-7680 a^{3} b \,{\mathrm e}^{4 i \left (d x +c \right )}-75 a^{4} {\mathrm e}^{i \left (d x +c \right )}-120 b^{4} {\mathrm e}^{i \left (d x +c \right )}+120 b^{4} {\mathrm e}^{11 i \left (d x +c \right )}+425 a^{4} {\mathrm e}^{9 i \left (d x +c \right )}+360 b^{4} {\mathrm e}^{9 i \left (d x +c \right )}-360 b^{4} {\mathrm e}^{3 i \left (d x +c \right )}-240 b^{4} {\mathrm e}^{5 i \left (d x +c \right )}-425 a^{4} {\mathrm e}^{3 i \left (d x +c \right )}+990 a^{4} {\mathrm e}^{7 i \left (d x +c \right )}+240 b^{4} {\mathrm e}^{7 i \left (d x +c \right )}-990 a^{4} {\mathrm e}^{5 i \left (d x +c \right )}+75 a^{4} {\mathrm e}^{11 i \left (d x +c \right )}\right )}{120 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{6}}-\frac {5 a^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{16 d}-\frac {9 a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) b^{2}}{4 d}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) b^{4}}{2 d}+\frac {5 a^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{16 d}+\frac {9 a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) b^{2}}{4 d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) b^{4}}{2 d}\) | \(541\) |
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Time = 0.28 (sec) , antiderivative size = 217, normalized size of antiderivative = 0.98 \[ \int (a+b \cos (c+d x))^4 \sec ^7(c+d x) \, dx=\frac {15 \, {\left (5 \, a^{4} + 36 \, a^{2} b^{2} + 8 \, b^{4}\right )} \cos \left (d x + c\right )^{6} \log \left (\sin \left (d x + c\right ) + 1\right ) - 15 \, {\left (5 \, a^{4} + 36 \, a^{2} b^{2} + 8 \, b^{4}\right )} \cos \left (d x + c\right )^{6} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (128 \, {\left (4 \, a^{3} b + 5 \, a b^{3}\right )} \cos \left (d x + c\right )^{5} + 192 \, a^{3} b \cos \left (d x + c\right ) + 15 \, {\left (5 \, a^{4} + 36 \, a^{2} b^{2} + 8 \, b^{4}\right )} \cos \left (d x + c\right )^{4} + 40 \, a^{4} + 64 \, {\left (4 \, a^{3} b + 5 \, a b^{3}\right )} \cos \left (d x + c\right )^{3} + 10 \, {\left (5 \, a^{4} + 36 \, a^{2} b^{2}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{480 \, d \cos \left (d x + c\right )^{6}} \]
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Timed out. \[ \int (a+b \cos (c+d x))^4 \sec ^7(c+d x) \, dx=\text {Timed out} \]
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Time = 0.19 (sec) , antiderivative size = 275, normalized size of antiderivative = 1.24 \[ \int (a+b \cos (c+d x))^4 \sec ^7(c+d x) \, dx=\frac {128 \, {\left (3 \, \tan \left (d x + c\right )^{5} + 10 \, \tan \left (d x + c\right )^{3} + 15 \, \tan \left (d x + c\right )\right )} a^{3} b + 640 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} a b^{3} - 5 \, a^{4} {\left (\frac {2 \, {\left (15 \, \sin \left (d x + c\right )^{5} - 40 \, \sin \left (d x + c\right )^{3} + 33 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{6} - 3 \, \sin \left (d x + c\right )^{4} + 3 \, \sin \left (d x + c\right )^{2} - 1} - 15 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 15 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 180 \, a^{2} b^{2} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 120 \, b^{4} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )}}{480 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 592 vs. \(2 (208) = 416\).
Time = 0.36 (sec) , antiderivative size = 592, normalized size of antiderivative = 2.67 \[ \int (a+b \cos (c+d x))^4 \sec ^7(c+d x) \, dx=\frac {15 \, {\left (5 \, a^{4} + 36 \, a^{2} b^{2} + 8 \, b^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 15 \, {\left (5 \, a^{4} + 36 \, a^{2} b^{2} + 8 \, b^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) + \frac {2 \, {\left (165 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 960 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 900 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 960 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 120 \, b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 25 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 2240 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 1260 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 3520 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 360 \, b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 450 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 4992 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 360 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 5760 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 240 \, b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 450 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 4992 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 360 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 5760 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 240 \, b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 25 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 2240 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 1260 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 3520 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 360 \, b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 165 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 960 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 900 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 960 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 120 \, b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{6}}}{240 \, d} \]
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Time = 18.89 (sec) , antiderivative size = 370, normalized size of antiderivative = 1.67 \[ \int (a+b \cos (c+d x))^4 \sec ^7(c+d x) \, dx=\frac {\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )\,\left (\frac {5\,a^4}{8}+\frac {9\,a^2\,b^2}{2}+b^4\right )}{d}+\frac {\left (\frac {11\,a^4}{8}-8\,a^3\,b+\frac {15\,a^2\,b^2}{2}-8\,a\,b^3+b^4\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}+\left (\frac {5\,a^4}{24}+\frac {56\,a^3\,b}{3}-\frac {21\,a^2\,b^2}{2}+\frac {88\,a\,b^3}{3}-3\,b^4\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9+\left (\frac {15\,a^4}{4}-\frac {208\,a^3\,b}{5}+3\,a^2\,b^2-48\,a\,b^3+2\,b^4\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+\left (\frac {15\,a^4}{4}+\frac {208\,a^3\,b}{5}+3\,a^2\,b^2+48\,a\,b^3+2\,b^4\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+\left (\frac {5\,a^4}{24}-\frac {56\,a^3\,b}{3}-\frac {21\,a^2\,b^2}{2}-\frac {88\,a\,b^3}{3}-3\,b^4\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\left (\frac {11\,a^4}{8}+8\,a^3\,b+\frac {15\,a^2\,b^2}{2}+8\,a\,b^3+b^4\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}-6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+15\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8-20\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+15\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )} \]
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